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0 votes

in below code messagebox.show not invoking.

in rea = new RRecord(path); method call it will work. again  mdd.DeleteOne(rea, remove); method call it will not work.

Please provide the solution

 using (RecordExpectations recorder = RecorderManager.StartRecording())
            {
                MessageBox.Show(null);
                recorder.Return(DialogResult.OK);
            }

            rea = new RRecord(path);
            Isolate.NonPublic.WhenCalled(aed, \"RExist\").WithExactArguments(\"rec\").WillReturn(false);
            mdd.DeleteOne(rea, remove);

asked by gnanam (5.2k points)

1 Answer

0 votes

Hey gnanam,

I apologize, I did not understand your question.

 Could you please clarify your request with more details& code? 

What \"aed\" stands for?

in rea = new RRecord(path); method call it will work. again mdd.DeleteOne(rea, remove); method call it will not work.

 

\"method call it will not work\" - What do you mean by that? the method will not be invoked?

answered by CoralTypemock (700 points)
rea = new RRecord(path);
...