How Can I fake an instance of an interface?

Question

Hi,

I have an interface defined with no class implementation. Can I fake an instance of an class which implement this interface or I need to create a dummy class implementing it first?

Thanks.

dhelper · Answer 1 · 2009-03-03T11:06:10+0000

One of Isolator strengths is creating fake objects from interfaces without any implementation:

var fake = Isolate.Fake.Instance<IClass>();

Should work just fine

How Can I fake an instance of an interface?

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Products

Help

Company

Community

Contact

Typemock Store (US toll FREE 866–895–4680). Copyright © 2006 Typemock Inc. All rights reserved. Terms of Use.

Choose the product type:

Related questions

How Can I fake an instance of an interface?

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Products

Help

Company

Community

Contact

Typemock Store (US toll FREE 866–895–4680). Copyright © 2006 Typemock Inc. All rights reserved. Terms of Use.